What is the domain of f(x)= x/(x^2+16x+60) ?

The domain of f(x)= x/(x^2+16x+60) is x -6

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domain of f(x)= x/(x^2+16x+60)

domain

f (x) = \frac{x}{x ^{2} + 16 x + 60}

x < - 10 or - 10 < x < - 6 or x > - 6

Interval Notation

(- \infty, - 10) \cup (- 10, - 6) \cup (- 6, \infty)

Solution steps

Find undefined (singularity) points:

x = - 6, x = - 10

The function domain

x < - 10 or - 10 < x < - 6 or x > - 6

3 x - 5 = 0

- 4 x^{2} + 16 x + 47

m = 0, (3, 2)

lo g_{2} (7 - x)

(6, 0), (0, 3)

What is the domain of f(x)= x/(x^2+16x+60) ?
The domain of f(x)= x/(x^2+16x+60) is x<-10\lor-10<x<-6\lor x>-6