What is the inverse of e^{3/(z^2)} ?

The inverse of e^{3/(z^2)} is sqrt(3/(ln(z))),-sqrt(3/(ln(z)))

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inverse of e^{3/(z^2)}

inverse

e^{\frac{3}{z ^{2}}}

\frac{3}{ln ( z )}, - \frac{3}{ln ( z )}

Solution steps

y = e^{\frac{3}{z ^{2}}}

Replace

z

with

y

z = e^{\frac{3}{y ^{2}}}

Solve for

y, z = e^{\frac{3}{y ^{2}}}

\frac{3}{ln ( z )}, - \frac{3}{ln ( z )}

f (x) = \frac{5}{3} x - \frac{5}{3}

f (x) = 2 x^{5} + 3

x + \frac{1}{x}

f (x) = \frac{x ^{7}}{7} - 4

31

What is the inverse of e^{3/(z^2)} ?
The inverse of e^{3/(z^2)} is sqrt(3/(ln(z))),-sqrt(3/(ln(z)))