What is the inverse of f(x)=(x^{1/5})/3+10 ?

The inverse of f(x)=(x^{1/5})/3+10 is 243x^5-12150x^4+243000x^3-2430000x^2+12150000x-24300000

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inverse of f(x)=(x^{1/5})/3+10

inverse

f (x) = \frac{x ^{\frac{1}{5}}}{3} + 10

243 x^{5} - 12150 x^{4} + 243000 x^{3} - 2430000 x^{2} + 12150000 x - 24300000

Solution steps

y = \frac{x ^{\frac{1}{5}}}{3} + 10

Replace

x

with

y

x = \frac{y ^{\frac{1}{5}}}{3} + 10

Solve for

y, x = \frac{y ^{\frac{1}{5}}}{3} + 10

243 x^{5} - 12150 x^{4} + 243000 x^{3} - 2430000 x^{2} + 12150000 x - 24300000

\frac{1}{4} x - 3

f (x) = \frac{1}{2} x + 10

f (x) = \frac{1}{2} x + 15

f (x) = 3 (\frac{x + 4}{4})^{\frac{1}{5}}

f (x) = cosh (x)

What is the inverse of f(x)=(x^{1/5})/3+10 ?
The inverse of f(x)=(x^{1/5})/3+10 is 243x^5-12150x^4+243000x^3-2430000x^2+12150000x-24300000