What is the inverse of f(x)= 3/(2+x^2) ?

The inverse of f(x)= 3/(2+x^2) is sqrt((3-2x)/x),-sqrt((3-2x)/x)

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inverse of f(x)= 3/(2+x^2)

inverse

f (x) = \frac{3}{2 + x ^{2}}

\frac{3 - 2 x}{x}, - \frac{3 - 2 x}{x}

Solution steps

y = \frac{3}{2 + x ^{2}}

Replace

x

with

y

x = \frac{3}{2 + y ^{2}}

Solve for

y, x = \frac{3}{2 + y ^{2}}

\frac{3 - 2 x}{x}, - \frac{3 - 2 x}{x}

f (x) = \frac{5 + 3 x}{x - 1}

f (x) = (x + 2)^{3} - 3

g (x) = \frac{1}{5} x

\frac{e ^{x} - 1}{e ^{x} + 1}

f (x) = \frac{3}{- x - 2}

What is the inverse of f(x)= 3/(2+x^2) ?
The inverse of f(x)= 3/(2+x^2) is sqrt((3-2x)/x),-sqrt((3-2x)/x)