What is the inverse of f(x)=((2x-1))/((x+3)) ?

The inverse of f(x)=((2x-1))/((x+3)) is (-1-3x)/(x-2)

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inverse of f(x)=((2x-1))/((x+3))

inverse

f (x) = \frac{( 2 x - 1 )}{( x + 3 )}

\frac{- 1 - 3 x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 3}

Replace

x

with

y

x = \frac{2 y - 1}{y + 3}

Solve for

y, x = \frac{2 y - 1}{y + 3}

\frac{- 1 - 3 x}{x - 2}

\frac{8}{1 - \frac{1}{z}} - \frac{9}{1 - 0.5 \frac{1}{z}} + 2

y = - 3 x + 2

f (x) = \frac{5}{9 x}

f (x) = \frac{1}{1 + e ^{x}}

What is the inverse of f(x)=((2x-1))/((x+3)) ?
The inverse of f(x)=((2x-1))/((x+3)) is (-1-3x)/(x-2)