What is the inverse of f(x)= 2/3 x^3-1 ?

The inverse of f(x)= 2/3 x^3-1 is cube root of (3x+3)/2

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inverse of f(x)= 2/3 x^3-1

inverse

f (x) = \frac{2}{3} x^{3} - 1

Solution steps

y = \frac{2}{3} x^{3} - 1

Replace

x

with

y

x = \frac{2}{3} y^{3} - 1

Solve for

y, x = \frac{2}{3} y^{3} - 1

f (x) = \frac{2 x + 7}{- 4 x}

f (x) = 3 x + 4

f (x) = 9 x - 10

x - 2 + 3

y = arctan (x)

What is the inverse of f(x)= 2/3 x^3-1 ?
The inverse of f(x)= 2/3 x^3-1 is cube root of (3x+3)/2