What is the inverse of f(x)=2(x-1)^2-3 ?

The inverse of f(x)=2(x-1)^2-3 is sqrt((x+3)/2)+1,-sqrt((x+3)/2)+1

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inverse of f(x)=2(x-1)^2-3

inverse

f (x) = 2 (x - 1)^{2} - 3

\frac{x + 3}{2} + 1, - \frac{x + 3}{2} + 1

Solution steps

y = 2 (x - 1)^{2} - 3

Replace

x

with

y

x = 2 (y - 1)^{2} - 3

Solve for

y, x = 2 (y - 1)^{2} - 3

\frac{x + 3}{2} + 1, - \frac{x + 3}{2} + 1

f (x) = 4 (x - 3)^{2} + 2

f (x) = 10 0^{x}

\frac{d}{d} x^{3}

f (x) = x + 7 - 4

f (x) = arcsin (- \frac{1}{2})

What is the inverse of f(x)=2(x-1)^2-3 ?
The inverse of f(x)=2(x-1)^2-3 is sqrt((x+3)/2)+1,-sqrt((x+3)/2)+1