What is the inverse of f(x)=-\sqrt[3]{n}-3 ?

The inverse of f(x)=-\sqrt[3]{n}-3 is -27-27n-9n^2-n^3

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inverse of f(x)=-\sqrt[3]{n}-3

inverse

f (x) = - 3 n - 3

- 27 - 27 n - 9 n^{2} - n^{3}

Solution steps

y = - 3 n - 3

Replace

n

with

y

n = - 3 y - 3

Solve for

y, n = - 3 y - 3

- 27 - 27 n - 9 n^{2} - n^{3}

f (x) = - \frac{5}{4} x - 6

f (x) = e^{2 x} - 6 e^{x} + 5

f (x) = e^{- x} + 2

f (x) = 7 x - 21

5 x (6 - x)

What is the inverse of f(x)=-\sqrt[3]{n}-3 ?
The inverse of f(x)=-\sqrt[3]{n}-3 is -27-27n-9n^2-n^3