What is the inverse of 2*3^x+9^x+3 ?

The inverse of 2*3^x+9^x+3 is (ln(-1+sqrt(x-2)))/(ln(3)),(ln(-sqrt(x-2)-1))/(ln(3))

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inverse of 2*3^x+9^x+3

inverse

2 \cdot 3^{x} + 9^{x} + 3

\frac{ln ( - 1 + x - 2 )}{ln ( 3 )}, \frac{ln ( - x - 2 - 1 )}{ln ( 3 )}

Solution steps

y = 2 \cdot 3^{x} + 9^{x} + 3

Replace

x

with

y

x = 2 \cdot 3^{y} + 9^{y} + 3

Solve for

y, x = 2 \cdot 3^{y} + 9^{y} + 3

\frac{ln ( - 1 + x - 2 )}{ln ( 3 )}, \frac{ln ( - x - 2 - 1 )}{ln ( 3 )}

p (x) = x^{2} + 1

f (x) = \frac{x ^{2} + 3}{2 x - 5}

f (x) = \frac{3}{2}

f (x) = 41 - 1.25 x

What is the inverse of 2*3^x+9^x+3 ?
The inverse of 2*3^x+9^x+3 is (ln(-1+sqrt(x-2)))/(ln(3)),(ln(-sqrt(x-2)-1))/(ln(3))