What is the inverse of f(x)=8x-2x^2 ?

The inverse of f(x)=8x-2x^2 is -(-8+sqrt(64-8x))/4 ,-(-8-sqrt(64-8x))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=8x-2x^2

inverse

f (x) = 8 x - 2 x^{2}

- \frac{- 8 + 64 - 8 x}{4}, - \frac{- 8 - 64 - 8 x}{4}

Solution steps

y = 8 x - 2 x^{2}

Replace

x

with

y

x = 8 y - 2 y^{2}

Solve for

y, x = 8 y - 2 y^{2}

- \frac{- 8 + 64 - 8 x}{4}, - \frac{- 8 - 64 - 8 x}{4}

f (x) = x + x - 1

f (x) = \frac{3}{2} cos (5 x - \frac{π}{4})

f (x) = \frac{- 3 x - 4}{x - 2}

f (x) = 5 - 2 x - 3, - 2 \leq x < 2

f (x) = 2 - 7 x

What is the inverse of f(x)=8x-2x^2 ?
The inverse of f(x)=8x-2x^2 is -(-8+sqrt(64-8x))/4 ,-(-8-sqrt(64-8x))/4