What is the inverse of f(x)=(\sqrt[3]{x})/2+9 ?

The inverse of f(x)=(\sqrt[3]{x})/2+9 is 8x^3-216x^2+1944x-5832

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inverse of f(x)=(\sqrt[3]{x})/2+9

inverse

f (x) = \frac{3 x}{2} + 9

8 x^{3} - 216 x^{2} + 1944 x - 5832

Solution steps

y = \frac{3 x}{2} + 9

Replace

x

with

y

x = \frac{3 y}{2} + 9

Solve for

y, x = \frac{3 y}{2} + 9

8 x^{3} - 216 x^{2} + 1944 x - 5832

f (x) = \frac{1}{5} x + \frac{3}{5}

\frac{x}{6}

f (x) = \frac{2 x + 17}{3 x + 1}

f (x) = x + 5 + 2

\frac{4}{3} x^{3}

What is the inverse of f(x)=(\sqrt[3]{x})/2+9 ?
The inverse of f(x)=(\sqrt[3]{x})/2+9 is 8x^3-216x^2+1944x-5832