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midpoint
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domain of f(x)= 3/(4sqrt(5/2+3/2 x))domain distance (0,1),(4,4)distance inverse of f(x)=(2x)/5+2inverse inverse of f(x)=25x+200inverse domain of 1/(2sqrt(a))domain
Frequently Asked Questions (FAQ)
What is the midpoint (-8,-1),(-8,-3) ?
The midpoint (-8,-1),(-8,-3) is (-8,-2)