What is the inverse of f(x)=4sqrt(x)-x,0<= x<= 1 ?

The inverse of f(x)=4sqrt(x)-x,0<= x<= 1 is -x+8+4sqrt(-x+4),-x+8-4sqrt(-x+4)

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inverse of f(x)=4sqrt(x)-x,0<= x<= 1

inverse

f (x) = 4 x - x, 0 \leq x \leq 1

- x + 8 + 4 - x + 4, - x + 8 - 4 - x + 4

Solution steps

y = 4 x - x

Replace

x

with

y

x = 4 y - y

Solve for

y, x = 4 y - y

- x + 8 + 4 - x + 4, - x + 8 - 4 - x + 4

f (x) = \frac{2 x - 3}{x}

f (x) = 10 (x + 10)^{\frac{1}{7}} - 5

f (x) = 3 x + \frac{1}{2}

f (x) = \frac{x}{2 x - 5}

f (x) = - 4 x^{2} + 4

What is the inverse of f(x)=4sqrt(x)-x,0<= x<= 1 ?
The inverse of f(x)=4sqrt(x)-x,0<= x<= 1 is -x+8+4sqrt(-x+4),-x+8-4sqrt(-x+4)