What is the inverse of y(d)=(d-12)/(2d+1) ?

The inverse of y(d)=(d-12)/(2d+1) is (-12-d)/(2d-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y(d)=(d-12)/(2d+1)

inverse

y (d) = \frac{d - 12}{2 d + 1}

\frac{- 12 - d}{2 d - 1}

Solution steps

y = \frac{d - 12}{2 d + 1}

Replace

d

with

y

d = \frac{y - 12}{2 y + 1}

Solve for

y, d = \frac{y - 12}{2 y + 1}

\frac{- 12 - d}{2 d - 1}

f (x) = \frac{8 x}{x - 3}

\frac{d}{d} x

f (x) = \frac{5 x + 2}{x - 2}

\frac{4}{- x - 2} + 2

arcsin (- \frac{3}{2})

What is the inverse of y(d)=(d-12)/(2d+1) ?
The inverse of y(d)=(d-12)/(2d+1) is (-12-d)/(2d-1)