What is the inverse of f(x)=2x^2-3x+5 ?

The inverse of f(x)=2x^2-3x+5 is (3+sqrt(8x-31))/4 ,(3-sqrt(8x-31))/4

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inverse of f(x)=2x^2-3x+5

inverse

f (x) = 2 x^{2} - 3 x + 5

\frac{3 + 8 x - 31}{4}, \frac{3 - 8 x - 31}{4}

Solution steps

y = 2 x^{2} - 3 x + 5

Replace

x

with

y

x = 2 y^{2} - 3 y + 5

Solve for

y, x = 2 y^{2} - 3 y + 5

\frac{3 + 8 x - 31}{4}, \frac{3 - 8 x - 31}{4}

(x + 3)^{5}

f (x) = \frac{3 x - 4}{2 x}

- x^{2} + 4 x - 3

f (x) = \frac{3}{x + 3}

f (x) = 3 - x + 8

What is the inverse of f(x)=2x^2-3x+5 ?
The inverse of f(x)=2x^2-3x+5 is (3+sqrt(8x-31))/4 ,(3-sqrt(8x-31))/4