What is the inverse of f(x)=sqrt(x^3+8) ?

The inverse of f(x)=sqrt(x^3+8) is cube root of x^2-8

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inverse of f(x)=sqrt(x^3+8)

inverse

f (x) = x^{3} + 8

Solution steps

y = x^{3} + 8

Replace

x

with

y

x = y^{3} + 8

Solve for

y, x = y^{3} + 8

y = 1 - x^{2}

f (x) = (x - 5)^{3} + 9

f (x) = \frac{5}{x + 2} - 4

f (x) = \frac{1}{2 x - 4}

f (x) = \frac{5 x - 20}{8}

What is the inverse of f(x)=sqrt(x^3+8) ?
The inverse of f(x)=sqrt(x^3+8) is cube root of x^2-8