What is the domain of (x^2-1)/(x+1) ?

The domain of (x^2-1)/(x+1) is x -1

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domain of (x^2-1)/(x+1)

domain

\frac{x ^{2} - 1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

x^{x}

(98, 5), (2, - 5)

f (x) = 3 x^{2} - 6 x

f (x) = \frac{4}{x + 9}

f (x) = \frac{x - 6}{x + 1}

What is the domain of (x^2-1)/(x+1) ?
The domain of (x^2-1)/(x+1) is x<-1\lor x>-1