What is the inverse of f(x)=4\sqrt[5]{x-1}+2 ?

The inverse of f(x)=4\sqrt[5]{x-1}+2 is 31/32+(x^5)/(1024)-(5x^4)/(512)+(5x^3)/(128)+(-5x^2+5x)/(64)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=4\sqrt[5]{x-1}+2

inverse

\frac{31}{32} + \frac{x ^{5}}{1024} - \frac{5 x ^{4}}{512} + \frac{5 x ^{3}}{128} + \frac{- 5 x ^{2} + 5 x}{64}

Solution steps

Replace

x

with

y

Solve for

\frac{31}{32} + \frac{x ^{5}}{1024} - \frac{5 x ^{4}}{512} + \frac{5 x ^{3}}{128} + \frac{- 5 x ^{2} + 5 x}{64}

f (x) = \frac{3 x}{2 x - 5}

3 x (6 - x)

f (x) = \frac{2 + x}{x}

f (x) = \frac{4 x ^{2} - 1}{2}

f (x) = \frac{2 x + 6}{3}

What is the inverse of f(x)=4\sqrt[5]{x-1}+2 ?
The inverse of f(x)=4\sqrt[5]{x-1}+2 is 31/32+(x^5)/(1024)-(5x^4)/(512)+(5x^3)/(128)+(-5x^2+5x)/(64)