What is the inverse of f(x)=(x+1)^2-4 ?

The inverse of f(x)=(x+1)^2-4 is sqrt(x+4)-1,-sqrt(x+4)-1

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inverse of f(x)=(x+1)^2-4

inverse

f (x) = (x + 1)^{2} - 4

x + 4 - 1, - x + 4 - 1

Solution steps

y = (x + 1)^{2} - 4

Replace

x

with

y

x = (y + 1)^{2} - 4

Solve for

y, x = (y + 1)^{2} - 4

x + 4 - 1, - x + 4 - 1

k (x) = x - 2

f (x) = 4 x + 8

f (x) = 2 - lo g_{3} (x + 1)

f (x) = (3 x - 5)^{\frac{1}{3}}

What is the inverse of f(x)=(x+1)^2-4 ?
The inverse of f(x)=(x+1)^2-4 is sqrt(x+4)-1,-sqrt(x+4)-1