What is the inverse of f(x)= 1/2 x^2+1 ?

The inverse of f(x)= 1/2 x^2+1 is sqrt(2x-2),-sqrt(2x-2)

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inverse of f(x)= 1/2 x^2+1

inverse

f (x) = \frac{1}{2} x^{2} + 1

2 x - 2, - 2 x - 2

Solution steps

y = \frac{1}{2} x^{2} + 1

Replace

x

with

y

x = \frac{1}{2} y^{2} + 1

Solve for

y, x = \frac{1}{2} y^{2} + 1

2 x - 2, - 2 x - 2

cos (2)

f (x) = arctan (- 1)

f (x) = - (x + 2)

f (x) = 6 x + 11

What is the inverse of f(x)= 1/2 x^2+1 ?
The inverse of f(x)= 1/2 x^2+1 is sqrt(2x-2),-sqrt(2x-2)