What is the inverse of f(x)=log_{3}(x-2)-1 ?

The inverse of f(x)=log_{3}(x-2)-1 is 3^{x+1}+2

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inverse of f(x)=log_{3}(x-2)-1

inverse

f (x) = lo g_{3} (x - 2) - 1

3^{x + 1} + 2

Solution steps

y = lo g_{3} (x - 2) - 1

Replace

x

with

y

x = lo g_{3} (y - 2) - 1

Solve for

y, x = lo g_{3} (y - 2) - 1

3^{x + 1} + 2

f (x) = \frac{3}{2 x - 5}

h (x) = - \frac{x}{4}

f (x) = \frac{3}{2 x - 4}

f (x) = \frac{- 8 x + 11}{- 2 x - 5}

f (x) = - 3 (x - 4)^{3} - 9

What is the inverse of f(x)=log_{3}(x-2)-1 ?
The inverse of f(x)=log_{3}(x-2)-1 is 3^{x+1}+2