What is the inverse of f(x)=-1/2 x^2 ?

The inverse of f(x)=-1/2 x^2 is sqrt(2)sqrt(-x),-sqrt(2)sqrt(-x)

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inverse of f(x)=-1/2 x^2

inverse

f (x) = - \frac{1}{2} x^{2}

2 - x, - 2 - x

Solution steps

y = - \frac{1}{2} x^{2}

Replace

x

with

y

x = - \frac{1}{2} y^{2}

Solve for

y, x = - \frac{1}{2} y^{2}

2 - x, - 2 - x

f (x) = \frac{4 x + 6}{5}

f (x) = x^{2} - 14 x

f (x) = \frac{7 x}{8 x - 1}

g (x) = x + 4 - 3

What is the inverse of f(x)=-1/2 x^2 ?
The inverse of f(x)=-1/2 x^2 is sqrt(2)sqrt(-x),-sqrt(2)sqrt(-x)