What is the inverse of f(x)=x^2+3x-5 ?

The inverse of f(x)=x^2+3x-5 is (-3+sqrt(4x+29))/2 ,(-3-sqrt(4x+29))/2

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inverse of f(x)=x^2+3x-5

inverse

f (x) = x^{2} + 3 x - 5

\frac{- 3 + 4 x + 29}{2}, \frac{- 3 - 4 x + 29}{2}

Solution steps

y = x^{2} + 3 x - 5

Replace

x

with

y

x = y^{2} + 3 y - 5

Solve for

y, x = y^{2} + 3 y - 5

\frac{- 3 + 4 x + 29}{2}, \frac{- 3 - 4 x + 29}{2}

f (x) = \frac{3 x + 3}{3 x - 7}

f (x) = \frac{3}{x} + 6

f (x) = \frac{x - 2}{x + 4}

f (x) = 3^{x - 2} + 1

What is the inverse of f(x)=x^2+3x-5 ?
The inverse of f(x)=x^2+3x-5 is (-3+sqrt(4x+29))/2 ,(-3-sqrt(4x+29))/2