What is the inverse of f(x)=((1+e^x))/((1-e^x)) ?

The inverse of f(x)=((1+e^x))/((1-e^x)) is ln(-(1-x)/(1+x))

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inverse of f(x)=((1+e^x))/((1-e^x))

inverse

f (x) = \frac{( 1 + e ^{x} )}{( 1 - e ^{x} )}

ln (- \frac{1 - x}{1 + x})

Solution steps

y = \frac{1 + e ^{x}}{1 - e ^{x}}

Replace

x

with

y

x = \frac{1 + e ^{y}}{1 - e ^{y}}

Solve for

y, x = \frac{1 + e ^{y}}{1 - e ^{y}}

ln (- \frac{1 - x}{1 + x})

f (x) = 2 x + 7 + 5

f (x) = \frac{3}{x + 2} - 2

f (x) = 20 - 20 e^{- l n (10) \cdot x}

f (x) = 4 (x + 3)^{2}

f (x) = \frac{( 3 - 2 x )}{3 x + b}

What is the inverse of f(x)=((1+e^x))/((1-e^x)) ?
The inverse of f(x)=((1+e^x))/((1-e^x)) is ln(-(1-x)/(1+x))