What is the inverse of f(x)=(x^2+3)/2 ?

The inverse of f(x)=(x^2+3)/2 is sqrt(2x-3),-sqrt(2x-3)

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inverse of f(x)=(x^2+3)/2

inverse

f (x) = \frac{x ^{2} + 3}{2}

2 x - 3, - 2 x - 3

Solution steps

y = \frac{x ^{2} + 3}{2}

Replace

x

with

y

x = \frac{y ^{2} + 3}{2}

Solve for

y, x = \frac{y ^{2} + 3}{2}

2 x - 3, - 2 x - 3

f (x) = \frac{x + 24}{x - 6}

\frac{3}{x} + 4

f (x) = \frac{- 2 x - 9}{- 6 x - 7}

f (x) = - 8 x

f (x) = - 7 x

What is the inverse of f(x)=(x^2+3)/2 ?
The inverse of f(x)=(x^2+3)/2 is sqrt(2x-3),-sqrt(2x-3)