What is the inverse of f(x)=(6x)/(sqrt(x^2-1)) ?

The inverse of f(x)=(6x)/(sqrt(x^2-1)) is (xsqrt(x^2-36))/(x^2-36),-(xsqrt(x^2-36))/(x^2-36)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(6x)/(sqrt(x^2-1))

inverse

f (x) = \frac{6 x}{x ^{2} - 1}

\frac{x x ^{2} - 36}{x ^{2} - 36}, - \frac{x x ^{2} - 36}{x ^{2} - 36}

Solution steps

y = \frac{6 x}{x ^{2} - 1}

Replace

x

with

y

x = \frac{6 y}{y ^{2} - 1}

Solve for

y, x = \frac{6 y}{y ^{2} - 1}

\frac{x x ^{2} - 36}{x ^{2} - 36}, - \frac{x x ^{2} - 36}{x ^{2} - 36}

lo g_{6} (x + 2)

\frac{1}{3} lo g_{2} (x) + 1

f (x) = - x - 3 + 4

f (x) = \frac{5}{6} x + 10

h (w) = 3 w - 4

What is the inverse of f(x)=(6x)/(sqrt(x^2-1)) ?
The inverse of f(x)=(6x)/(sqrt(x^2-1)) is (xsqrt(x^2-36))/(x^2-36),-(xsqrt(x^2-36))/(x^2-36)