What is the inverse of f(x)=x^2+2x-8 ?

The inverse of f(x)=x^2+2x-8 is -1+sqrt(x+9),-sqrt(x+9)-1

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inverse of f(x)=x^2+2x-8

inverse

f (x) = x^{2} + 2 x - 8

- 1 + x + 9, - x + 9 - 1

Solution steps

y = x^{2} + 2 x - 8

Replace

x

with

y

x = y^{2} + 2 y - 8

Solve for

y, x = y^{2} + 2 y - 8

- 1 + x + 9, - x + 9 - 1

y = a^{x}

lo g_{2} (k x - 6)

f (x) = 8 + 0.75 x

f (x) = \frac{- 2 x + 1}{- x - 1}

y = 3 x - 8

What is the inverse of f(x)=x^2+2x-8 ?
The inverse of f(x)=x^2+2x-8 is -1+sqrt(x+9),-sqrt(x+9)-1