What is the inverse of y=(4x-1)/(2x+3) ?

The inverse of y=(4x-1)/(2x+3) is (-1-3x)/(2(-2+x))

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inverse of y=(4x-1)/(2x+3)

inverse

y = \frac{4 x - 1}{2 x + 3}

\frac{- 1 - 3 x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 1}{2 x + 3}

Replace

x

with

y

x = \frac{4 y - 1}{2 y + 3}

Solve for

y, x = \frac{4 y - 1}{2 y + 3}

\frac{- 1 - 3 x}{2 ( - 2 + x )}

\frac{x ^{2} - 1}{x - 1}

f (x) = - \frac{6}{2 x - 5}

g (x) = \frac{1}{x ^{2}}

\frac{1}{3} x + 3

f (x) = 3 + (x - 2)^{2}

What is the inverse of y=(4x-1)/(2x+3) ?
The inverse of y=(4x-1)/(2x+3) is (-1-3x)/(2(-2+x))