What is the inverse of f(x)=2(x-5)^2-3 ?

The inverse of f(x)=2(x-5)^2-3 is sqrt((x+3)/2)+5,-sqrt((x+3)/2)+5

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inverse of f(x)=2(x-5)^2-3

inverse

f (x) = 2 (x - 5)^{2} - 3

\frac{x + 3}{2} + 5, - \frac{x + 3}{2} + 5

Solution steps

y = 2 (x - 5)^{2} - 3

Replace

x

with

y

x = 2 (y - 5)^{2} - 3

Solve for

y, x = 2 (y - 5)^{2} - 3

\frac{x + 3}{2} + 5, - \frac{x + 3}{2} + 5

f (x) = 6 15 - x - 3

\frac{2 x}{x - 2}

f (x) = \frac{x - 2}{2 x - 3}

f (x) = 3 + 4 + 7 x

\frac{1}{- x - 2}

What is the inverse of f(x)=2(x-5)^2-3 ?
The inverse of f(x)=2(x-5)^2-3 is sqrt((x+3)/2)+5,-sqrt((x+3)/2)+5