What is the inverse of f(x)= 1/2 log_{10}(2x) ?

The inverse of f(x)= 1/2 log_{10}(2x) is 25^x*2^{2x-1}

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inverse of f(x)= 1/2 log_{10}(2x)

inverse

f (x) = \frac{1}{2} lo g_{10} (2 x)

2 5^{x} \cdot 2^{2 x - 1}

Solution steps

y = \frac{1}{2} lo g_{10} (2 x)

Replace

x

with

y

x = \frac{1}{2} lo g_{10} (2 y)

Solve for

y, x = \frac{1}{2} lo g_{10} (2 y)

2 5^{x} \cdot 2^{2 x - 1}

f (x) = \frac{2 x + 4}{5}

e^{x} - 1

f (x) = 4 x + 25

f (x) = - \frac{2}{x + 3}

f (x) = (x - 5)^{3} + 2

What is the inverse of f(x)= 1/2 log_{10}(2x) ?
The inverse of f(x)= 1/2 log_{10}(2x) is 25^x*2^{2x-1}