What is the inverse of (x^2+3x-10)/(x^2+10x+25) ?

The inverse of (x^2+3x-10)/(x^2+10x+25) is (-2-5x)/(x-1)

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inverse of (x^2+3x-10)/(x^2+10x+25)

inverse

\frac{x ^{2} + 3 x - 10}{x ^{2} + 10 x + 25}

\frac{- 2 - 5 x}{x - 1}

Solution steps

y = \frac{x ^{2} + 3 x - 10}{x ^{2} + 10 x + 25}

Replace

x

with

y

x = \frac{y ^{2} + 3 y - 10}{y ^{2} + 10 y + 25}

Solve for

y, x = \frac{y ^{2} + 3 y - 10}{y ^{2} + 10 y + 25}

\frac{- 2 - 5 x}{x - 1}

f (x) = 3 ln (x)

f (x) = x \frac{1}{4} - 3

f (x) = - \frac{1}{2} x - 3

y = x - x^{2}

tan (- 1)

What is the inverse of (x^2+3x-10)/(x^2+10x+25) ?
The inverse of (x^2+3x-10)/(x^2+10x+25) is (-2-5x)/(x-1)