What is the inverse of f(x)=x^2-12x,x>= 6 ?

The inverse of f(x)=x^2-12x,x>= 6 is 6+sqrt(x+36),6-sqrt(x+36)

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inverse of f(x)=x^2-12x,x>= 6

inverse

f (x) = x^{2} - 12 x, x \geq 6

6 + x + 36, 6 - x + 36

Solution steps

y = x^{2} - 12 x

Replace

x

with

y

x = y^{2} - 12 y

Solve for

y, x = y^{2} - 12 y

6 + x + 36, 6 - x + 36

f (x) = 3 x + 13

f (x) = \frac{x ^{3}}{8}

f (x) = 3 x - 20

f (x) = 6 x - 24

2 x - 2

What is the inverse of f(x)=x^2-12x,x>= 6 ?
The inverse of f(x)=x^2-12x,x>= 6 is 6+sqrt(x+36),6-sqrt(x+36)