What is the inverse of f(x)=(x-1)^2-3,x>= 1 ?

The inverse of f(x)=(x-1)^2-3,x>= 1 is sqrt(x+3)+1,-sqrt(x+3)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-1)^2-3,x>= 1

inverse

f (x) = (x - 1)^{2} - 3, x \geq 1

x + 3 + 1, - x + 3 + 1

Solution steps

y = (x - 1)^{2} - 3

Replace

x

with

y

x = (y - 1)^{2} - 3

Solve for

y, x = (y - 1)^{2} - 3

x + 3 + 1, - x + 3 + 1

y = - \frac{3}{x}

x^{2} - 7 x + 12

f (x) = - \frac{2}{3} x + 5

y = \frac{- x}{x + 1}

f (x) = \frac{2 x + 3}{4 x - 1}

What is the inverse of f(x)=(x-1)^2-3,x>= 1 ?
The inverse of f(x)=(x-1)^2-3,x>= 1 is sqrt(x+3)+1,-sqrt(x+3)+1