What is the inverse of f(x)=5x^2-1 ?

The inverse of f(x)=5x^2-1 is sqrt((x+1)/5),-sqrt((x+1)/5)

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inverse of f(x)=5x^2-1

inverse

f (x) = 5 x^{2} - 1

\frac{x + 1}{5}, - \frac{x + 1}{5}

Solution steps

y = 5 x^{2} - 1

Replace

x

with

y

x = 5 y^{2} - 1

Solve for

y, x = 5 y^{2} - 1

\frac{x + 1}{5}, - \frac{x + 1}{5}

f (x) = 5 x - 13

f (x) = \frac{9}{2 + x}

f (x) = - x^{2} + 6 x - 5

f (x) = \frac{2 x - 3}{x - 4}

y = 2 x^{3}

What is the inverse of f(x)=5x^2-1 ?
The inverse of f(x)=5x^2-1 is sqrt((x+1)/5),-sqrt((x+1)/5)