What is the inverse of f(x)= 1/6 x^3-8 ?

The inverse of f(x)= 1/6 x^3-8 is cube root of 6x+48

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inverse of f(x)= 1/6 x^3-8

inverse

f (x) = \frac{1}{6} x^{3} - 8

Solution steps

y = \frac{1}{6} x^{3} - 8

Replace

x

with

y

x = \frac{1}{6} y^{3} - 8

Solve for

y, x = \frac{1}{6} y^{3} - 8

f (x) = 2 ln (\frac{x + 5}{3})

f (x) = ln (2 x + 1)

\frac{3 x + 2}{x}

2 x^{2} + 4 x + 3

f (x) = 11 x + 7

What is the inverse of f(x)= 1/6 x^3-8 ?
The inverse of f(x)= 1/6 x^3-8 is cube root of 6x+48