What is the inverse of 2(x-2)^2=8(7+y) ?

The inverse of 2(x-2)^2=8(7+y) is 2sqrt(x+7)+2,-2sqrt(x+7)+2

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inverse of 2(x-2)^2=8(7+y)

inverse

2 (x - 2)^{2} = 8 (7 + y)

2 x + 7 + 2, - 2 x + 7 + 2

Solution steps

y = \frac{( x - 2 ) ^{2}}{4} - 7

Replace

x

with

y

x = \frac{( y - 2 ) ^{2}}{4} - 7

Solve for

y, x = \frac{( y - 2 ) ^{2}}{4} - 7

2 x + 7 + 2, - 2 x + 7 + 2

f (x) = \frac{4 + x}{x}

f (x) = \frac{3 x}{5} + 1

f (x) = - \frac{3}{4} x + \frac{5}{2}

f (x) = \frac{5 x + 3}{2 x - 1}

y = \frac{x - 1}{x + 2}

What is the inverse of 2(x-2)^2=8(7+y) ?
The inverse of 2(x-2)^2=8(7+y) is 2sqrt(x+7)+2,-2sqrt(x+7)+2