What is the inverse of f(x)=-4x^2-20x+16 ?

The inverse of f(x)=-4x^2-20x+16 is -(5+sqrt(-x+41))/2 ,-(5-sqrt(-x+41))/2

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inverse of f(x)=-4x^2-20x+16

inverse

f (x) = - 4 x^{2} - 20 x + 16

- \frac{5 + - x + 41}{2}, - \frac{5 - - x + 41}{2}

Solution steps

y = - 4 x^{2} - 20 x + 16

Replace

x

with

y

x = - 4 y^{2} - 20 y + 16

Solve for

y, x = - 4 y^{2} - 20 y + 16

- \frac{5 + - x + 41}{2}, - \frac{5 - - x + 41}{2}

f (x) = \frac{- 10}{1 - 4 x}

f (x) = 0.6 x - 2

f (x) = 10 0^{t}

f (x) = \frac{8 x}{x ^{2} - 1}

x^{2} - 4 x + 7

What is the inverse of f(x)=-4x^2-20x+16 ?
The inverse of f(x)=-4x^2-20x+16 is -(5+sqrt(-x+41))/2 ,-(5-sqrt(-x+41))/2