What is the inverse of f(x)=\sqrt[3]{(3x+1)/2} ?

The inverse of f(x)=\sqrt[3]{(3x+1)/2} is (2x^3-1)/3

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inverse of f(x)=\sqrt[3]{(3x+1)/2}

inverse

\frac{2 x ^{3} - 1}{3}

Solution steps

Replace

x

with

y

Solve for

\frac{2 x ^{3} - 1}{3}

f (x) = 3 + 4^{x}

f (x) = 32 - 20 e^{- 0.4 x}

f (x) = 2 x^{2} + 24 x - 3

4 x^{2} - 25

g (x) = - 2 x

What is the inverse of f(x)=\sqrt[3]{(3x+1)/2} ?
The inverse of f(x)=\sqrt[3]{(3x+1)/2} is (2x^3-1)/3