What is the inverse of f(x)=x^2+x-2 ?

The inverse of f(x)=x^2+x-2 is (-1+sqrt(4x+9))/2 ,(-1-sqrt(4x+9))/2

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inverse of f(x)=x^2+x-2

inverse

f (x) = x^{2} + x - 2

\frac{- 1 + 4 x + 9}{2}, \frac{- 1 - 4 x + 9}{2}

Solution steps

y = x^{2} + x - 2

Replace

x

with

y

x = y^{2} + y - 2

Solve for

y, x = y^{2} + y - 2

\frac{- 1 + 4 x + 9}{2}, \frac{- 1 - 4 x + 9}{2}

f (x) = x - 2 + 6

arccos (- \frac{3}{2})

f (x) = 3^{x} + 4

f (x) = 3^{x} - 4

f (x) = x^{\frac{1}{3}} + 4

What is the inverse of f(x)=x^2+x-2 ?
The inverse of f(x)=x^2+x-2 is (-1+sqrt(4x+9))/2 ,(-1-sqrt(4x+9))/2