What is the inverse of f(x)=(x^2-2)/3 ?

The inverse of f(x)=(x^2-2)/3 is sqrt(3x+2),-sqrt(3x+2)

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inverse of f(x)=(x^2-2)/3

inverse

f (x) = \frac{x ^{2} - 2}{3}

3 x + 2, - 3 x + 2

Solution steps

y = \frac{x ^{2} - 2}{3}

Replace

x

with

y

x = \frac{y ^{2} - 2}{3}

Solve for

y, x = \frac{y ^{2} - 2}{3}

3 x + 2, - 3 x + 2

f (x) = \frac{2 x + 7}{x + 1}

2^{2 x}

f (x) = \frac{- 12 - 2 x}{3}

f (x) = 2 + 5 + 9 x

f (x) = \frac{( x - 1 )}{x ^{2} - 1}

What is the inverse of f(x)=(x^2-2)/3 ?
The inverse of f(x)=(x^2-2)/3 is sqrt(3x+2),-sqrt(3x+2)