What is the inverse of f(x)=x^2-3x+5 ?

The inverse of f(x)=x^2-3x+5 is (3+sqrt(4x-11))/2 ,(3-sqrt(4x-11))/2

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inverse of f(x)=x^2-3x+5

inverse

f (x) = x^{2} - 3 x + 5

\frac{3 + 4 x - 11}{2}, \frac{3 - 4 x - 11}{2}

Solution steps

y = x^{2} - 3 x + 5

Replace

x

with

y

x = y^{2} - 3 y + 5

Solve for

y, x = y^{2} - 3 y + 5

\frac{3 + 4 x - 11}{2}, \frac{3 - 4 x - 11}{2}

5 - x + 3

- 3 x + 7

\frac{2 - 7 x}{9 - 5 x}

- 3 x - 3

f (x) = \frac{x - 2}{x - 1}

What is the inverse of f(x)=x^2-3x+5 ?
The inverse of f(x)=x^2-3x+5 is (3+sqrt(4x-11))/2 ,(3-sqrt(4x-11))/2