What is the inverse of f(y)=2y-y^2 ?

The inverse of f(y)=2y-y^2 is 1-sqrt(-y+1),sqrt(-y+1)+1

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inverse of f(y)=2y-y^2

inverse

f (y) = 2 y - y^{2}

1 - - y + 1, - y + 1 + 1

Solution steps

y = 2 y - y^{2}

Replace

y

with

y

y = 2 y - y^{2}

Solve for

y, y = 2 y - y^{2}

1 - - y + 1, - y + 1 + 1

f (x) = \frac{1 - x}{3}

f (x) = \frac{6}{x + 1}

f (x) = - (x + 3)^{2}

f (x) = x - 2 + 5

f (x) = - (x + 3)^{3}

What is the inverse of f(y)=2y-y^2 ?
The inverse of f(y)=2y-y^2 is 1-sqrt(-y+1),sqrt(-y+1)+1