What is the inverse of g(x)=4x^2+8 ?

The inverse of g(x)=4x^2+8 is (sqrt(x-8))/2 ,-(sqrt(x-8))/2

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inverse of g(x)=4x^2+8

inverse

g (x) = 4 x^{2} + 8

\frac{x - 8}{2}, - \frac{x - 8}{2}

Solution steps

y = 4 x^{2} + 8

Replace

x

with

y

x = 4 y^{2} + 8

Solve for

y, x = 4 y^{2} + 8

\frac{x - 8}{2}, - \frac{x - 8}{2}

\frac{1}{2} x^{2} - 1

f (x) = - x^{2} + 10 x - 15

f (x) = x + 4 + 1

\frac{3 x}{2 x + 1}

f (x) = 2^{c o s (x)}

What is the inverse of g(x)=4x^2+8 ?
The inverse of g(x)=4x^2+8 is (sqrt(x-8))/2 ,-(sqrt(x-8))/2