What is the inverse of g(x)=4x^2-12 ?

The inverse of g(x)=4x^2-12 is (sqrt(x+12))/2 ,-(sqrt(x+12))/2

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inverse of g(x)=4x^2-12

inverse

g (x) = 4 x^{2} - 12

\frac{x + 12}{2}, - \frac{x + 12}{2}

Solution steps

y = 4 x^{2} - 12

Replace

x

with

y

x = 4 y^{2} - 12

Solve for

y, x = 4 y^{2} - 12

\frac{x + 12}{2}, - \frac{x + 12}{2}

f (x) = \frac{2 - x}{2 + x}

f (x) = \frac{- 7}{8 + 3 x}

arcsin (\frac{2}{2})

y = \frac{5 ^{x}}{1 + 5 ^{x}}

What is the inverse of g(x)=4x^2-12 ?
The inverse of g(x)=4x^2-12 is (sqrt(x+12))/2 ,-(sqrt(x+12))/2