What is the inverse of sqrt(1/(x^2+1)) ?

The inverse of sqrt(1/(x^2+1)) is (sqrt(1-x^2))/x ,-(sqrt(1-x^2))/x

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inverse of sqrt(1/(x^2+1))

inverse

\frac{1}{x ^{2} + 1}

\frac{1 - x ^{2}}{x}, - \frac{1 - x ^{2}}{x}

Solution steps

y = \frac{1}{x ^{2} + 1}

Replace

x

with

y

x = \frac{1}{y ^{2} + 1}

Solve for

y, x = \frac{1}{y ^{2} + 1}

\frac{1 - x ^{2}}{x}, - \frac{1 - x ^{2}}{x}

f (x) = lo g_{10} (2 x)

f (x) = - 1 + x, x \geq 1

f (x) = ln (2 x) - 3

g (x) = 2 x + 4

f (x) = - e^{x}

What is the inverse of sqrt(1/(x^2+1)) ?
The inverse of sqrt(1/(x^2+1)) is (sqrt(1-x^2))/x ,-(sqrt(1-x^2))/x