What is the inverse of f(x)=3(\sqrt[3]{x}-1)+10 ?

The inverse of f(x)=3(\sqrt[3]{x}-1)+10 is (x^3}{27}-\frac{7x^2)/9+(49x)/9-343/27

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inverse of f(x)=3(\sqrt[3]{x}-1)+10

inverse

\frac{x ^{3}}{27} - \frac{7 x ^{2}}{9} + \frac{49 x}{9} - \frac{343}{27}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{27} - \frac{7 x ^{2}}{9} + \frac{49 x}{9} - \frac{343}{27}

f (x) = \frac{3 x}{4 - x}

\frac{7}{( x - 4 ) ^{2}}

f (x) = \frac{1}{3} (x - 2)^{2} + 8

2 ln (\frac{x + 3}{5})

What is the inverse of f(x)=3(\sqrt[3]{x}-1)+10 ?
The inverse of f(x)=3(\sqrt[3]{x}-1)+10 is (x^3}{27}-\frac{7x^2)/9+(49x)/9-343/27