What is the critical (x^3(x-5)^2)/(54) ?

The critical (x^3(x-5)^2)/(54) is x=0,x=3,x=5

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critical (x^3(x-5)^2)/(54)

critical points

\frac{x ^{3} ( x - 5 ) ^{2}}{54}

x = 0, x = 3, x = 5

Solution steps

\frac{x ^{3} ( x - 5 ) ^{2}}{54}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 3, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3} ( x - 5 ) ^{2}}{54} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 3, x = 5

f (x) = \frac{x + 1}{x - 3}

f (x) = \frac{x ^{2} - 2 x - 8}{x - 6}

(- 5, - 4), (9, 2)

(- 5, - 6), (- 3, - 8)

f (x) = \frac{98}{x ^{3}}

What is the critical (x^3(x-5)^2)/(54) ?
The critical (x^3(x-5)^2)/(54) is x=0,x=3,x=5