What is the inverse of (2x)/(sqrt(x^2-1)) ?

The inverse of (2x)/(sqrt(x^2-1)) is (xsqrt(x^2-4))/(x^2-4),-(xsqrt(x^2-4))/(x^2-4)

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inverse of (2x)/(sqrt(x^2-1))

inverse

\frac{2 x}{x ^{2} - 1}

\frac{x x ^{2} - 4}{x ^{2} - 4}, - \frac{x x ^{2} - 4}{x ^{2} - 4}

Solution steps

y = \frac{2 x}{x ^{2} - 1}

Replace

x

with

y

x = \frac{2 y}{y ^{2} - 1}

Solve for

y, x = \frac{2 y}{y ^{2} - 1}

\frac{x x ^{2} - 4}{x ^{2} - 4}, - \frac{x x ^{2} - 4}{x ^{2} - 4}

f (x) = ln (x + 3) + 5

f (x) = \frac{4 x}{x + 1}

g (x) = 4 x - 7

f (x) = \frac{2 x + 5}{3 x - 4}

What is the inverse of (2x)/(sqrt(x^2-1)) ?
The inverse of (2x)/(sqrt(x^2-1)) is (xsqrt(x^2-4))/(x^2-4),-(xsqrt(x^2-4))/(x^2-4)