What is the inverse of f(x)= 1/6 log_{3}(-3x)+2 ?

The inverse of f(x)= 1/6 log_{3}(-3x)+2 is -3^{6x-13}

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inverse of f(x)= 1/6 log_{3}(-3x)+2

inverse

f (x) = \frac{1}{6} lo g_{3} (- 3 x) + 2

- 3^{6 x - 13}

Solution steps

y = \frac{1}{6} lo g_{3} (- 3 x) + 2

Replace

x

with

y

x = \frac{1}{6} lo g_{3} (- 3 y) + 2

Solve for

y, x = \frac{1}{6} lo g_{3} (- 3 y) + 2

- 3^{6 x - 13}

f (x) = 0. 8^{x}

f (x) = \frac{2}{n} + 2

f (x) = \frac{5 x + 8}{- 3 x - 1}

f (x) = \frac{3 - x}{5 - x}

What is the inverse of f(x)= 1/6 log_{3}(-3x)+2 ?
The inverse of f(x)= 1/6 log_{3}(-3x)+2 is -3^{6x-13}