What is the inverse of sqrt(2x-x^2) ?

The inverse of sqrt(2x-x^2) is 1-sqrt(-x^2+1),sqrt(-x^2+1)+1

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inverse of sqrt(2x-x^2)

inverse

2 x - x^{2}

1 - - x^{2} + 1, - x^{2} + 1 + 1

Solution steps

y = 2 x - x^{2}

Replace

x

with

y

x = 2 y - y^{2}

Solve for

y, x = 2 y - y^{2}

1 - - x^{2} + 1, - x^{2} + 1 + 1

\frac{1}{3} x + 2

\frac{x + 1}{2}

f (x) = \frac{x}{x + 1} + 1

f (x) = \frac{3}{x + 1} + 2

\frac{2 ^{x}}{2 ^{x} - 1}

What is the inverse of sqrt(2x-x^2) ?
The inverse of sqrt(2x-x^2) is 1-sqrt(-x^2+1),sqrt(-x^2+1)+1